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Mathematics - Multivariable Calculus - Lecture 1

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Multivariable CalculusInstructor: Edward Frenkelcourse website: http://math.berkeley.edu/~fren...

Channel: Education
Uploaded: November 30, 1999 at 12:00 am
Author: UCBerkeley

Length: 19:50
Rating: 4.84
Views: 46127

Tags: uc  berkeley  ucberkeley  webcast.berkeley  cal  mathematics  calculus  multivariable  

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jeffstukas (November 30, 1999 at 12:00 am)
this instructor is a rock star
PharaohDaniyal (November 30, 1999 at 12:00 am)
Mmm this is orgasmic. As a sixteen year old math-fag, I <3 this. My stupid highschool teachers are 2 noob to make me orgasm like this does.
hikeh101 (November 30, 1999 at 12:00 am)
@boot819 tuesday thursday classes are 1 hour and 20 min
Schutzstafell (November 30, 1999 at 12:00 am)
@urbaneinspiration Wanna know why a plane doesn't fall out of the sky right on to your fat head? Calculus.. Physics.. Chemistry, etc. So his teachings keep you alive. Be grateful :)
urbaneinspiration (November 30, 1999 at 12:00 am)
This guy gets paid over $150 K per year for talking BS that no one uses? That goes for most professors!
50poiuyt (November 30, 1999 at 12:00 am)
mathematical award
amriteighteen (November 30, 1999 at 12:00 am)
This guy is such a cool teacher. I would want a professor like him when I go to university.
kari3ma (November 30, 1999 at 12:00 am)
he is so hot... lol
infantileretard (November 30, 1999 at 12:00 am)
@clark3249 first of all, a = 2 not 1/2 in your expression. So x^2/4 + y^2/1 = 1 is an ellipse. Now look at my original statement below where I said 4x^2 + y^2 =1 is a circle - > 4* 1/4 * cos^2(t) = cos^2(t) ; got it?
infantileretard (November 30, 1999 at 12:00 am)
@clark3249 a = 0.5, b=1; then multiply x^2/a^2 by 4 - > 4 * 0.5^2 * cos(t) = cos (t); so back to my original statement "4x^2 + y^2 = 1 is still a circle". Get it?